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Cambridge 0580 IGCSE  ·  Topic C1.12

C1.12 Rates

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01 — Explanation

What is a rate, and how does the speed formula triangle work?

A rate compares two quantities in different units — the word "per" always signals division. The most common rate in this topic is speed:

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Cover up the quantity you want to find:

Speed=DistanceTime,Distance=Speed×Time,Time=DistanceSpeed\text{Speed} = \frac{\text{Distance}}{\text{Time}}, \qquad \text{Distance} = \text{Speed} \times \text{Time}, \qquad \text{Time} = \frac{\text{Distance}}{\text{Speed}}

02 — Explanation

How do I convert minutes into decimal hours for use in the formula?

Since time runs in base 60, divide the minutes by 6060:

15 min=0.25 h,30 min=0.5 h,40 min=0.66‾ h15 \text{ min} = 0.25\text{ h}, \quad 30 \text{ min} = 0.5\text{ h}, \quad 40 \text{ min} = 0.6\overline{6}\text{ h}

Common Slip

writing 11 hour 3030 minutes as 1.301.30 hours. It should be 1.51.5 hours — the 3030 minutes must be divided by 6060 first, not written as if it were a decimal already.

Example: a cyclist rides 54 km54\text{ km} in 11 hour 3030 minutes. Her average speed is:

Speed=541.5=36 km/h\text{Speed} = \frac{54}{1.5} = 36 \text{ km/h}

03 — Explanation

How do I find the average speed of a journey with more than one stage?

Average speed is always total distancetotal time\dfrac{\text{total distance}}{\text{total time}} — you cannot just average the individual speeds together.

Example: a car travels 80 km80\text{ km} at 40 km/h40\text{ km/h}, then 60 km60\text{ km} at 30 km/h30\text{ km/h}. Find the average speed for the whole journey.

  1. Time for stage 1: 8040=2 h\dfrac{80}{40} = 2\text{ h}.
  2. Time for stage 2: 6030=2 h\dfrac{60}{30} = 2\text{ h}.
  3. Total distance =80+60=140 km= 80+60=140\text{ km}; total time =2+2=4 h= 2+2=4\text{ h}.
  4. Average speed =1404=35 km/h= \dfrac{140}{4} = 35 \text{ km/h}.

Exam Tip

here, averaging 4040 and 3030 directly also happens to give 3535 — but that's a coincidence caused by equal times for each stage. Always use the total distance ÷ total time method, since it isn't reliable otherwise.

04 — Explanation

How do rates like density work, using the same triangle method?

Any rate that links two quantities with a "per" relationship can use the same cover-up triangle idea as speed. Density is one of the most common examples:

Density=MassVolume,Mass=Density×Volume,Volume=MassDensity\text{Density} = \frac{\text{Mass}}{\text{Volume}}, \qquad \text{Mass} = \text{Density} \times \text{Volume}, \qquad \text{Volume} = \frac{\text{Mass}}{\text{Density}}

Example: a metal block has a mass of 270 g270\text{ g} and a volume of 30 cm330\text{ cm}^3. Find its density, then find the mass of a second block of the same metal with volume 50 cm350\text{ cm}^3.

  1. Density of block 1: 27030=9 g/cm3\dfrac{270}{30}=9\text{ g/cm}^3.
  2. Since block 2 is the same metal, it has the same density.
  3. Mass of block 2: 9×50=450 g9 \times 50 = 450\text{ g}.

The required formula will always be given in the question if it isn't speed, but you're still expected to know how to rearrange and substitute into it — exactly as with the speed triangle.

05 — Common mistakes

Common mistakes to avoid

  • Writing minutes as a decimal directly, e.g. 11 hour 3030 min as 1.301.30 instead of 1.51.5.
  • Averaging two speeds by adding and halving them rather than using total distance over total time.
  • Forgetting to convert km/h to m/s (divide by 3.63.6) or m/s to km/h (multiply by 3.63.6) when units in the question don't match.