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Cambridge 0580 IGCSE  ·  Topic E4.3

E4.3 Scale Drawings and Bearings

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01 — Explanation

How does a scale drawing represent real distances?

A scale (e.g. "1 cm represents 200 m1\text{ cm represents } 200\text{ m}") lets you shrink real-world distances onto paper proportionally. To find a real distance, measure it on the drawing with a ruler, then multiply by the scale. To find a length to draw, divide the real distance by the scale.

02 — Explanation

How do I work with a scale written as a ratio, like 1 : 50\,000?

A ratio scale means "11 unit on the drawing represents 50 00050\,000 of the same unit in real life" — so if the drawing is in centimetres, 1 cm1\text{ cm} represents 50 000 cm50\,000\text{ cm}, which you then convert into a more sensible unit (here, 500 m500\text{ m}, since 50 000÷100=50050\,000 \div 100 = 500). Always convert the real-world answer into metres or kilometres at the end rather than leaving it in an awkward number of centimetres.

03 — Explanation

What exactly is a three-figure bearing?

A bearing gives a direction as an angle measured clockwise from north, always written using three digits (e.g. 025°025°, not 25°25°). Bearings run from 000°000° to 360°360°, so north itself is 000°000° (or equivalently 360°360°), east is 090°090°, south is 180°180°, and west is 270°270°.

04 — Explanation

How do I find a "back bearing" — the bearing of B from A, given the bearing of A from B?

Draw a quick sketch with north lines at both points. Because the north lines at AA and BB are parallel, alternate angles let you connect the two bearings:

  • If the given bearing is less than 180°180°, add 180°180°.
  • If the given bearing is 180°180° or more, subtract 180°180°.
Bearing of A from B=Bearing of B from A ± 180°\text{Bearing of } A \text{ from } B = \text{Bearing of } B \text{ from } A \ \pm \ 180°

05 — Explanation

How do bearings combine with scale drawings in one question?

A typical question gives a bearing and a distance from a starting point (e.g. "a ship sails 8 km8\text{ km} on a bearing of 070°070°"). Draw a north line at the start point, use a protractor to mark the bearing angle clockwise from it, then use your scale to mark off the correct length along that direction.

Exam tip

Always draw a small north arrow (↑) at every point you're taking a bearing from, not just the first one — bearing angles are only ever measured from north at that specific point, never from the previous line of travel.

06 — Worked example

Worked example

The bearing of BB from AA is 025°025°. Find the bearing of AA from BB.

  1. Since 025°025° is less than 180°180°, add 180°180°: 025°+180°=205°025° + 180° = 205°.
  2. The bearing of AA from BB is 205°205°.

07 — Worked example

Worked example: using a ratio scale

A map has a scale of 1:25 0001 : 25\,000. Two towns are 6.4 cm6.4\text{ cm} apart on the map. Find the real distance between them in kilometres.

  1. Real distance =6.4×25 000=160 000 cm= 6.4 \times 25\,000 = 160\,000\text{ cm}.
  2. Convert cm to m (÷100\div 100): 160 000÷100=1600 m160\,000 \div 100 = 1600\text{ m}.
  3. Convert m to km (÷1000\div 1000): 1600÷1000=1.6 km1600 \div 1000 = 1.6\text{ km}.