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Cambridge 0580 IGCSE  ·  Topic C1.7

C1.7 Indices I

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01 — Explanation

What do positive, zero and negative indices mean?

An index tells you how many times a base is multiplied by itself: ana^n means aa multiplied by itself nn times.

  • A zero index always gives 11: a0=1a^0 = 1 (for a≠0a \neq 0), e.g. 90=19^0 = 1.
  • A negative index means "take the reciprocal of the positive power": a−n=1ana^{-n} = \dfrac{1}{a^n}, e.g. 2−3=182^{-3} = \dfrac{1}{8}.

Core tier only covers positive, zero and negative integer indices — fractional indices are Extended-only.

Common Slip

the word "negative" makes people think the answer must be negative. It doesn't — 4−2=1164^{-2} = \frac{1}{16}, which is positive. A negative index only ever flips the number to its reciprocal.

02 — Explanation

What are the index laws for multiplying and dividing powers?

These only work when the base is the same:

am×an=am+ne.g.x2×x5=x7a^m \times a^n = a^{m+n} \qquad \text{e.g.} \quad x^2 \times x^5 = x^7
am÷an=am−ne.g.y8÷y3=y5a^m \div a^n = a^{m-n} \qquad \text{e.g.} \quad y^8 \div y^3 = y^5

The base itself never changes — only the indices are added or subtracted. A common error is writing 32×34=963^2 \times 3^4 = 9^6; the correct working keeps the base as 33: 32×34=363^2 \times 3^4 = 3^6.

03 — Explanation

How do I simplify a power raised to another power?

Multiply the indices together:

(am)n=amne.g.(k2)4=k8(a^m)^n = a^{mn} \qquad \text{e.g.} \quad (k^2)^4 = k^8

04 — Explanation

What happens when I try to combine powers using addition instead of multiplication?

The index laws for adding exponents only apply when the terms are being multiplied or divided — they do not apply to addition or subtraction of powers. This is one of the most common sources of lost marks in this topic.

23+22≠252^3 + 2^2 \neq 2^5

To check: 23+22=8+4=122^3+2^2 = 8+4=12, but 25=322^5=32 — clearly not equal. When terms are added, you must work out each power's actual value first and then add the results; there is no shortcut rule for combining the indices themselves.

Common Slip

applying am×an=am+na^m \times a^n = a^{m+n} to a sum like am+ana^m + a^n. The index laws are strictly for multiplication and division of powers with the same base — always check which operation is actually being used before reaching for a law.

05 — Explanation

How do I combine more than one index law in the same question?

Work through the expression one operation at a time, applying the relevant law at each stage rather than trying to do everything in one jump.

Example: simplify a5×a2a4\dfrac{a^5 \times a^2}{a^4}.

  1. Apply the multiplication law to the numerator first: a5×a2=a5+2=a7a^5 \times a^2 = a^{5+2}=a^7.
  2. Now apply the division law: a7a4=a7−4=a3\dfrac{a^7}{a^4}=a^{7-4}=a^3.

06 — Worked example

Worked exam-style question

(a) Find the value of 2−32^{-3} and 50×325^0 \times 3^2.

(b) Simplify (23)2(2^3)^2 and x6x9\dfrac{x^6}{x^9}.

(a) 2−3=123=182^{-3} = \dfrac{1}{2^3} = \dfrac{1}{8}. Also, 50=15^0 = 1, so 50×32=1×9=95^0 \times 3^2 = 1 \times 9 = 9.

(b) (23)2=23×2=26=64(2^3)^2 = 2^{3\times2} = 2^6 = 64. Using the division law, x6x9=x6−9=x−3=1x3\dfrac{x^6}{x^9} = x^{6-9} = x^{-3} = \dfrac{1}{x^3}.

07 — Common mistakes

Common mistakes to avoid

  • Multiplying the base itself when multiplying two powers, e.g. writing 32×34=963^2 \times 3^4 = 9^6 instead of 363^6.
  • Believing a negative index makes the result negative — it means reciprocal, not negative.
  • Believing a0=0a^0 = 0. Any non-zero number to the power 00 equals 11, which follows from amam=a0=1\frac{a^m}{a^m} = a^0 = 1.