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Cambridge 0580 IGCSE  ·  Topic C4.4

C4.4 Similarity

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01 — Explanation

What makes two shapes similar?

Two shapes are similar when their corresponding angles are equal and their corresponding sides are all in the same ratio. Enlarging or shrinking a photograph produces a similar image: the shape is preserved, only the size changes. Because the angles must match exactly, checking angles is often the fastest way to prove two shapes are similar in the first place — if every angle in one triangle matches an angle in the other, the sides are automatically guaranteed to be in one consistent ratio.

02 — Explanation

How do I identify which sides correspond to each other?

Corresponding sides always sit opposite matching angles, so sketch and label both shapes' angles before deciding which sides pair up. This matters most when a diagram is drawn at an angle or one shape is rotated relative to the other — the "obviously matching" sides by position on the page are not always the true corresponding sides. Naming shapes consistently helps: in similar triangles ABCABC and XYZXYZ, the labelling itself tells you ABAB corresponds to XYXY, BCBC to YZYZ, and CACA to ZXZX, since vertices are listed in matching order.

03 — Explanation

How do I find the scale factor between similar shapes?

k=length on the new shapecorresponding length on the original shapek = \frac{\text{length on the new shape}}{\text{corresponding length on the original shape}}

04 — Explanation

How do I use the scale factor to find a missing length?

Once kk is known from one pair of corresponding sides, multiply any other known length by kk to find its corresponding length on the similar shape:

missing length=known corresponding length×k\text{missing length} = \text{known corresponding length} \times k

Worked example. Triangles ABCABC and XYZXYZ are similar, with ABAB corresponding to XYXY and BCBC corresponding to YZYZ. Given AB=4.5 cmAB = 4.5\text{ cm}, XY=9 cmXY = 9\text{ cm}, BC=6.2 cmBC = 6.2\text{ cm}, find YZYZ.

k=XYAB=94.5=2YZ=BC×k=6.2×2=12.4 cmk = \frac{XY}{AB} = \frac{9}{4.5} = 2 \qquad YZ = BC \times k = 6.2 \times 2 = 12.4\text{ cm}

Exam tip

check your answer makes sense before moving on — if the new shape is bigger, k>1k > 1 and every length should have grown; if it's smaller, k<1k < 1 and lengths should shrink. An answer that shrinks when it should have grown is a sign that kk was found upside down.

05 — Explanation

How does similarity apply to real-life shadow and height problems?

A classic exam context uses similar triangles formed by a vertical object and its shadow: the object, its shadow, and the sun's ray form one triangle; a shorter reference object (like a metre stick) and its own shadow, measured at the same moment, form a smaller similar triangle.

Worked example. A vertical flagpole casts a shadow 14 m14\text{ m} long. At the same time, a 1.2 m1.2\text{ m} stick standing nearby casts a shadow 2 m2\text{ m} long. Find the height of the flagpole.

Since both shadows are measured at the same time, the sun's angle is identical, so the two right-angled triangles (object, shadow, ray) are similar:

k=142=7flagpole height=1.2×7=8.4 mk = \frac{14}{2} = 7 \qquad \text{flagpole height} = 1.2 \times 7 = 8.4\text{ m}

Common mistake

pairing the flagpole's shadow with the stick's height (mismatched quantities) instead of matching shadow-to-shadow and height-to-height. Always confirm which measurements play the same role in each triangle before dividing.