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Cambridge 0580 IGCSE  ·  Topic E1.1

E1.1 Types of Number & Prime Factorisation

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01 — Explanation

What are the different types of number?

Every number belongs to one or more of these sets:

Number SetSymbolDefinitionExamples
Natural numbersN\mathbb{N}Positive counting numbers1,2,3,…1, 2, 3, \dots (00 excluded)
IntegersZ\mathbb{Z}Positive, negative, and zero whole numbers…,−2,−1,0,1,2,…\dots, -2, -1, 0, 1, 2, \dots
Rational numbersQ\mathbb{Q}Can be written as pq\frac{p}{q}, p,q∈Zp, q \in \mathbb{Z}, q≠0q \neq 034\frac{3}{4}, −5-5, 0.3˙0.\dot{3}
Irrational numbers—Cannot be written as an exact fractionπ\pi, 2\sqrt{2}, 5\sqrt{5}

A prime number has exactly two factors, 11 and itself. A reciprocal of xx is 1x\dfrac{1}{x} (x≠0x \neq 0).

Examiner Tip: 11 is not prime — it has only one factor, not two. This trips up more candidates than any other number fact on the syllabus.

02 — Explanation

How do I write a number as a product of its prime factors?

Repeatedly divide by the smallest prime that fits, until only primes remain, then collect the results using index notation. Every integer greater than 11 has exactly one such breakdown — the Fundamental Theorem of Arithmetic.

180=2×90=2×2×45=2×2×3×15=2×2×3×3×5=22×32×5180 = 2 \times 90 = 2 \times 2 \times 45 = 2\times2\times3\times15 = 2\times2\times3\times3\times5 = 2^2\times3^2\times5

03 — Explanation

How do I find the HCF and LCM using prime factorisation?

Write AA and BB in prime-factor form, then:

HCF(A,B)=product of the lowest shared power of each common prime\text{HCF}(A,B) = \text{product of the \textbf{lowest} shared power of each common prime}
LCM(A,B)=product of the highest power of every prime appearing in either number\text{LCM}(A,B) = \text{product of the \textbf{highest} power of every prime appearing in either number}

and always HCF(A,B)×LCM(A,B)=A×B\text{HCF}(A,B) \times \text{LCM}(A,B) = A \times B — a handy check.

Example: A=23×3×52A = 2^3 \times 3 \times 5^2, B=22×33×5B = 2^2 \times 3^3 \times 5.

HCF=22×31×51=60LCM=23×33×52=5400\text{HCF} = 2^2\times3^1\times5^1 = 60 \qquad \text{LCM} = 2^3\times3^3\times5^2=5400

Examiner Tip: Don't muddle the direction — HCF must divide into both numbers, so it can't exceed the smaller shared power; LCM must be divisible by both, so it needs the larger power.

04 — Explanation

How do I use prime factorisation to find a missing multiplier?

A number is a perfect square exactly when every exponent in its prime factorisation is even, and a perfect cube exactly when every exponent is a multiple of 33. To turn a number into a perfect square (or cube) with the smallest possible multiplier, factorise it and top up whichever exponents are "short".

Worked Example

Find the smallest positive integer kk such that 288k288k is a perfect square.

  1. Factorise: 288=25×32288 = 2^5 \times 3^2.
  2. The exponent of 22 is 55 (odd) — one more factor of 22 makes it 66 (even). The exponent of 33 is already even.
  3. So k=2k = 2, and 288×2=576=242288 \times 2 = 576 = 24^2. ✓

05 — Explanation

How do I decide whether a number is rational or irrational?

Ask whether it can be written exactly as a fraction pq\dfrac{p}{q} of two integers. A decimal that terminates (like 0.750.75) or recurs (like 0.3˙0.\dot{3}) is always rational, because both types convert to an exact fraction. A decimal that goes on forever with no repeating pattern — such as π\pi or 0.101001000100001…0.101001000100001\ldots — is irrational.

Roots are the most common trap: n\sqrt{n} is irrational unless nn is a perfect square, in which case the root symbol is hiding a whole number in disguise.

16=4 (rational — it’s just an integer)17≈4.123105… (irrational — never repeats)\sqrt{16} = 4 \ \text{(rational — it's just an integer)} \qquad \sqrt{17} \approx 4.123105\ldots \ \text{(irrational — never repeats)}

Examiner Tip: "Is 49\sqrt{49} rational or irrational?" is a genuine exam question, not just a warm-up. Always check for a perfect square hiding under the root before assuming a root must be irrational.