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Pearson Edexcel 4MA1 IGCSE  ·  Topic G2.9

G2.9 Solving One-Step Equations

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01 — Explanation

What does it actually mean to "solve" an equation?

An equation states that two expressions are equal; solving it means finding the value of the variable that makes this true. The equals sign is not an "answer button" — it's a statement of balance, like old-fashioned weighing scales. Whatever you do to one side, you must do identically to the other, or the balance is destroyed.

02 — Explanation

How do I use inverse operations to isolate the variable?

Identify what operation is being done to the variable, then apply its inverse to both sides: addition undoes subtraction (and vice versa), multiplication undoes division (and vice versa).

EquationOperation on variableInverse appliedSolution
k+18=21k+18=21+18+18−18-18 from both sidesk=3k=3
x−7=12x-7=12−7-7+7+7 to both sidesx=19x=19
2x=182x=18×2\times2÷2\div2 both sidesx=9x=9
x4=6\tfrac{x}{4}=6÷4\div4×4\times4 both sidesx=24x=24

Common Mistake

given x−4=13x-4=13, some students subtract 4 from both sides instead of recognising that the inverse of −4-4 is +4+4. Read the sign as part of the term: it tells you which inverse to use, not which operation to repeat.

03 — Explanation

How do I check my solution is correct?

Substitute your answer back into the original equation and confirm both sides match. For 2x=182x=18 with x=9x=9: 2×9=182\times9=18 ✓. This single habit catches almost every arithmetic slip before you move on.

Exam Tip

"Without sufficient working, correct answers may be awarded no marks" is explicit Edexcel guidance. A method mark (M1) is given for correctly applying the inverse operation even if an arithmetic error follows — so always show the step where you act on both sides, not just the final value.

04 — Worked example

Worked exam-style question

A one-step equation appears as the final stage of a longer geometry problem: having simplified an expression for a missing angle, a student arrives at 5y−16=295y - 16 = 29... but suppose instead the simplified equation is simply 5y=455y = 45. Solve for yy and verify your answer.

  1. The variable is multiplied by 5; the inverse is division.
  2. Divide both sides by 5: 5y5=455\dfrac{5y}{5} = \dfrac{45}{5}, giving y=9y=9.
  3. Check: 5×9=455 \times 9 = 45 ✓.

Answer: y=9y = 9.

Exam Tip

one-step equations rarely appear in isolation — they're usually the last line of a longer problem (angles, perimeters, word problems). Make solving them fast and automatic so you can focus your attention on setting the equation up correctly in the first place.

05 — Explanation

Why do some students get this wrong even when they "know the method"?

The usual cause isn't the algebra itself but the equals sign: in arithmetic it signals "here's the answer", but in algebra it signals "these two things balance". A student who hasn't made that mental shift will often perform an operation on only one side, destroying the balance. Explicitly thinking "whatever I do to the left, I must do to the right" before writing anything down prevents this.