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Pearson Edexcel 4MA1 IGCSE  ·  Topic G3.19

G3.19 Frequency Trees

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01 — Explanation

What is a frequency tree, and how is it different from a probability tree?

A frequency tree sorts a population by two successive categories, using actual counts at every node (always whole numbers) — unlike a probability tree, which uses fractions or decimals along the branches. At any point in the tree, the numbers on the branches leading out of a node must add up to the number entering it.

02 — Explanation

How do I fill in the missing values?

Place every value you're given directly, then use subtraction wherever a branch pair has one known and one unknown value — each node's total minus its known branch gives the missing branch.

Example: 30 students took a test; 23 passed. Number who failed: 30−23=730-23=7.

Keep working outward branch by branch, and as a final check, confirm that all the terminal (end) branches add back up to the overall total.

03 — Explanation

What if the data is given as a percentage or fraction, not a count?

Convert it to an integer immediately, before putting anything on the tree — never carry a percentage or fraction through the subtraction steps.

Example: 120120 people in total, two-fifths of whom are female: 25×120=48\frac{2}{5}\times120=48 females, so 120−48=72120-48=72 males.

Common Misconception: Subtracting using the fraction or percentage value itself instead of first converting it to a frequency. Always write the conversion step out explicitly, e.g. "120×0.4=48120\times0.4=48", so the whole-number count is what gets carried forward.

For a large population, it's often faster to calculate as many of the first-level frequencies as possible directly by multiplication (rather than leaving several to be found later by subtraction) — this reduces the number of places an earlier slip can cascade into a later answer.

04 — Explanation

How do I find a simple probability from the tree?

P(outcome)=frequency at that terminal nodetotal population NP(\text{outcome}) = \frac{\text{frequency at that terminal node}}{\text{total population } N}

Example: In a tree with total N=40N=40 and a terminal node of 1414 for "Male, likes coffee," P(Male and coffee)=1440=720P(\text{Male and coffee}) = \dfrac{14}{40} = \dfrac{7}{20}.

Exam Tip: Always simplify your final fraction, or convert to a decimal or percentage if the question asks for one — an unsimplified fraction like 1440\frac{14}{40} can cost you the final accuracy mark even with correct working.

05 — Explanation

How do I find a conditional probability ("given that...") from the tree?

The "given" group becomes the new, restricted total — not the full population NN.

Example: Of 80 people, 53 are left-handed, of whom 27 are female. Find P(female∣left-handed)P(\text{female}\mid\text{left-handed}).

P(female∣left-handed)=2753P(\text{female}\mid\text{left-handed}) = \frac{27}{53}

Common Misconception: Using the overall population NN as the denominator for a conditional probability. The phrase "given that..." always shrinks the sample space down to just that subgroup — identify its frequency first, and use that as the denominator.

06 — Worked example

Worked Example

A survey of 200 film fans found that 40% prefer action films. Of those who prefer action films, 70 are male. Of those who do not prefer action films, 50 are female.

  1. Convert the percentage: 200×0.40=80200\times0.40=80 prefer action; 200−80=120200-80=120 do not.
  2. Action branch: 7070 male, so 80−70=1080-70=10 female.
  3. Non-action branch: 5050 female, so 120−50=70120-50=70 male.
  4. Check: terminal nodes sum to 70+10+50+70=20070+10+50+70=200 ✓.
  5. Find P(male∣prefers action)P(\text{male}\mid\text{prefers action}): 7080=78\dfrac{70}{80}=\dfrac{7}{8}.