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Pearson Edexcel 4MA1 IGCSE  ·  Topic G6.12  ·  Higher tier

G6.12 Box Plots

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01 — Explanation

What are the five numbers, and what do they mean?

Minimum, lower quartile (Q1Q_1), median (Q2Q_2), upper quartile (Q3Q_3), maximum. The box runs from Q1Q_1 to Q3Q_3 (its width is the interquartile range, IQR=Q3−Q1\text{IQR}=Q_3-Q_1), the median is marked inside it, and whiskers stretch out to the minimum and maximum. Each of the four sections — below Q1Q_1, Q1Q_1–Q2Q_2, Q2Q_2–Q3Q_3, above Q3Q_3 — holds exactly 25% of the data.

02 — Explanation

How do I find Q_1 and Q_3 from a raw list of data?

Order the data first — always. Find the median, then take the median of each half separately: the lower half gives Q1Q_1, the upper half gives Q3Q_3.

Odd nn (7 values: 4,6,10,11,15,17,19): median is the 4th value, 1111 — and it's excluded from both halves. Lower half {4,6,10}⇒Q1=6\{4,6,10\}\Rightarrow Q_1=6; upper half {15,17,19}⇒Q3=17\{15,17,19\}\Rightarrow Q_3=17.

Even nn (8 values: 22,25,28,31,35,38,40,42): median =31+352=33=\frac{31+35}{2}=33; the data splits cleanly with nothing excluded. Lower half {22,25,28,31}⇒Q1=25+282=26.5\{22,25,28,31\}\Rightarrow Q_1=\frac{25+28}{2}=26.5; upper half {35,38,40,42}⇒Q3=39\{35,38,40,42\}\Rightarrow Q_3=39.

Exam Tip: whether the median gets excluded from the two halves depends only on whether nn is odd or even — this single detail is where most marks are lost in this method.

03 — Explanation

How do I estimate the five-number summary from a cumulative frequency graph?

Same logic as estimating a median from cumulative frequency, run three times. Find N4\frac{N}{4}, N2\frac{N}{2}, 3N4\frac{3N}{4} on the y-axis, read across to the curve and down to the x-axis for Q1Q_1, Q2Q_2, Q3Q_3. The minimum and maximum are simply where the curve starts and ends.

N=120N=120: positions 3030, 6060, 9090 give (say) Q1=35Q_1=35, median=42=42, Q3=51Q_3=51; if the curve runs from 2020 to 7070, those are the min/max. Five-number summary: {20,35,42,51,70}\{20, 35, 42, 51, 70\}.

04 — Explanation

How do I compare two box plots properly?

Never just list values from each plot — that scores poorly. Always compare two things, in context: the median (which group did better on average) and the IQR (which group was more consistent).

Weak answer: "Class A's median is 55, Class B's is 70." (This just restates numbers.)

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Strong answer: "Company B scored higher on average, with a median of 70 compared to Company A's 55. Company B's scores were also more consistent, shown by its smaller IQR of 5 compared to Company A's IQR of 10."

05 — Explanation

How do I identify outliers?

Use the 1.5×IQR1.5\times\text{IQR} rule to define fences beyond which a point counts as a statistical outlier:

Lower fence=Q1−1.5×IQRUpper fence=Q3+1.5×IQR\text{Lower fence} = Q_1 - 1.5\times\text{IQR} \qquad \text{Upper fence} = Q_3 + 1.5\times\text{IQR}

Any value outside these fences is plotted as a separate point (a cross or dot); the whisker itself then only extends to the last non-outlier value, not all the way to the true minimum/maximum.

06 — Worked example

Worked exam-style question

Company A's commute times (min): Q1=22Q_1=22, median=31=31, Q3=40Q_3=40. Company B's: Q1=18Q_1=18, median=25=25, Q3=48Q_3=48. Compare the two distributions.

  1. Medians: Company A (3131) has a longer typical commute than Company B (2525).
  2. IQRs: IQRA=40−22=18\text{IQR}_A = 40-22=18; IQRB=48−18=30\text{IQR}_B=48-18=30.
  3. Company A's commute times are more consistent (smaller IQR of 18) than Company B's (wider IQR of 30), even though Company A's typical commute is longer.

Notice the two findings can point in different directions — always report both the average and the spread, since a question can ask to compare them separately.