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Pearson Edexcel 4MA1 IGCSE  ·  Topic G7.6  ·  Higher tier

G7.6 Algebraic Fractions

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01 — Explanation

Why does almost every algebraic fraction question start with factorising?

Exam questions are built to simplify, so an algebraic fraction given to you almost always has a common factor hiding in its numerator and denominator. If you can factorise the easier side first, it tells you what factor to look for on the harder side.

Worked example: Simplify 4x+62x2−7x−15\dfrac{4x+6}{2x^2-7x-15}.

Numerator factors easily: 2(2x+3)2(2x+3). That strongly suggests (2x+3)(2x+3) is a factor of the denominator too — dividing confirms (2x2−7x−15)=(2x+3)(x−5)(2x^2-7x-15)=(2x+3)(x-5), so the fraction simplifies to 2x−5\dfrac{2}{x-5}.

Exam Tip: You can only cancel common factors (things multiplied), never common terms (things added/subtracted). x2+5x\dfrac{x^2+5}{x} does not simplify to x+5x+5.

02 — Explanation

How do I multiply and divide algebraic fractions?

Factorise everything first, cancel common factors (vertically or diagonally across the two fractions), then multiply what's left. For division, use "keep, change, flip" — keep the first fraction, change ÷ to ×, flip the second fraction — then proceed as a multiplication.

Worked example: x2−9x+4×x+43x+9\dfrac{x^2-9}{x+4}\times\dfrac{x+4}{3x+9}. Factorise: (x−3)(x+3)x+4×x+43(x+3)\dfrac{(x-3)(x+3)}{x+4}\times\dfrac{x+4}{3(x+3)}. Cancel (x+4)(x+4) diagonally and (x+3)(x+3) vertically, leaving x−33\dfrac{x-3}{3}.

03 — Explanation

How do I add or subtract algebraic fractions with different denominators?

Factorise every denominator before finding the common denominator — this often reveals that the "lowest" common denominator is much smaller than it first looks.

Worked example: 3x−1−2x2−1\dfrac{3}{x-1}-\dfrac{2}{x^2-1}. Since x2−1=(x−1)(x+1)x^2-1=(x-1)(x+1), the LCD is just (x−1)(x+1)(x-1)(x+1) — not the cubic you'd get by multiplying the denominators blindly.

Exam Tip: When subtracting, the whole numerator of the second fraction gets a minus sign in front of it. Put it in brackets before expanding: 4(x+2)−(3x+15)=4x+8−3x−154(x+2)-(3x+15)=4x+8-3x-15, not 4x+8−3x+154x+8-3x+15. This sign slip is the single most common error in this topic.

04 — Explanation

How do I solve an equation containing algebraic fractions?

Multiply every term by the LCD to clear all the fractions at once, then solve whatever's left — which might be linear or quadratic.

Linear case: Solve 3−5x+1=13-\dfrac{5}{x+1}=1.

Multiply by (x+1)(x+1): 3(x+1)−5=1(x+1)⇒3x−2=x+1⇒x=1.53(x+1)-5=1(x+1) \Rightarrow 3x-2=x+1 \Rightarrow x=1.5.

Quadratic case: Solve 9x+4x=−2x\dfrac{9x+4}{x}=-2x.

Multiply by xx: 9x+4=−2x2⇒2x2+9x+4=0⇒(2x+1)(x+4)=0⇒x=−129x+4=-2x^2 \Rightarrow 2x^2+9x+4=0 \Rightarrow (2x+1)(x+4)=0 \Rightarrow x=-\tfrac12 or x=−4x=-4.

Exam Tip: If clearing the fractions produces an x2x^2 term, that's your signal to stop manipulating fractions and switch entirely to "solve the quadratic" mode — rearrange to =0=0 and factorise or use the formula. Many students clear the fractions correctly and then freeze, not recognising what they're looking at.

05 — Worked example

Worked exam-style question

Solve 4x−1−3x+2=1\dfrac{4}{x-1}-\dfrac{3}{x+2}=1.

  1. Multiply every term by (x−1)(x+2)(x-1)(x+2): 4(x+2)−3(x−1)=(x−1)(x+2)4(x+2)-3(x-1)=(x-1)(x+2).
  2. Expand carefully: 4x+8−3x+3=x2+x−24x+8-3x+3 = x^2+x-2, giving x+11=x2+x−2x+11=x^2+x-2.
  3. Simplify: subtract xx from both sides → 11=x2−211=x^2-2.
  4. Rearrange to standard form: x2−13=0⇒x2=13x^2-13=0 \Rightarrow x^2=13.
  5. x=13x=\sqrt{13} or x=−13x=-\sqrt{13}.

Exam Tip: "Keep, change, flip" only applies to division — don't accidentally flip a fraction when the operation is actually multiplication.

Exam Tip: After solving, a question that asked you to "simplify" the original fraction (rather than solve an equation) only wants the factorised and cancelled form — don't go on to set it equal to zero or try to find values of xx unless the question explicitly says "solve".

06 — Common mistakes

Common mistakes to avoid

  • Cancelling individual terms instead of whole factors.
  • Dropping the sign on a subtracted numerator when it isn't bracketed.
  • Multiplying denominators together for the LCD without factorising first.
  • Reaching an x2x^2 equation and not switching to quadratic-solving methods.