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Pearson Edexcel 4MA1 IGCSE  ·  Topic G2.4

G2.4 Finding a Fraction of an Amount

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01 — Explanation

How do I find a unit fraction of an amount?

A unit fraction has numerator 1 (e.g. 14\tfrac{1}{4}). Finding a unit fraction of an amount is simply division by the denominator.

18 of 72=72÷8=9\tfrac{1}{8}\text{ of }72 = 72 \div 8 = 9

These are usually worth 1 mark (B1), awarded for the correct answer alone.

02 — Explanation

How do I find a non-unit fraction of an amount?

Use the two-step method: divide by the denominator, then multiply by the numerator. The division finds the value of one part; the multiplication scales it up to however many parts you need.

25 of 40:40÷5=8,8×2=16\tfrac{2}{5}\text{ of }40: \quad 40 \div 5 = 8, \qquad 8 \times 2 = 16

Why it works

dividing by the denominator finds 15\tfrac{1}{5} of the amount; since you want 2 of those fifths, you double it. Thinking of it this way — rather than as a memorised rule — stops you from accidentally swapping which number you divide by.

Exam Tip

these are usually worth 2 marks: M1 for showing the complete method (e.g. 72÷6 (=12)72 \div 6 \,(=12) and 12×512 \times 5), A1 for the correct final answer. Writing both lines of working protects your mark even if the final multiplication contains a slip.

03 — Explanation

How do I use this in a word problem with an extra step?

Read to the end of the question before calculating — many problems ask for the amount remaining, not the fraction itself.

Example: There are 40 apples in a crate. 310\tfrac{3}{10} are bad. How many good apples are there?

  1. Bad apples: 40÷10=440 \div 10 = 4, then 4×3=124 \times 3 = 12.
  2. Good apples: 40−12=2840 - 12 = 28.

A student who stops after step 1 and writes "12" has answered a different question and scores M1 A0 — always re-read the final command phrase before writing your answer.

04 — Worked example

Worked exam-style question

Harry has 50 sweets. He gives 25\tfrac{2}{5} of them to Sandra and 310\tfrac{3}{10} of them to Jamie. He keeps the rest for himself. How many sweets does Harry keep?

  1. Sandra's share: 50÷5=1050 \div 5 = 10, then 10×2=2010 \times 2 = 20.
  2. Jamie's share: 50÷10=550 \div 10 = 5, then 5×3=155 \times 3 = 15.
  3. Total given away: 20+15=3520 + 15 = 35.
  4. Harry keeps: 50−35=1550 - 35 = 15.

Answer: Harry keeps 15 sweets.

Common Mistake

Reversing the algorithm — multiplying by the denominator and dividing by the numerator (e.g. computing 40×10÷340\times10\div3 instead of 40÷10×340\div10\times3). If you're ever unsure, picture a bar split into the number of pieces given by the denominator: that step is always the division.

05 — Explanation

How does this connect to percentages and ratios?

A percentage is just a fraction out of 100, so "find 17% of 300" uses exactly the same two-step logic as a fraction question: divide by 100, then multiply by 17. Ratio-sharing problems (e.g. "share 60 in the ratio 2:3") also reduce to this skill once you find the total number of parts (2+3=52+3=5) — the problem becomes finding 25\tfrac{2}{5} and 35\tfrac{3}{5} of 60.