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Pearson Edexcel 4MA1 IGCSE  ·  Topic G3.3

G3.3 Estimation

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01 — Explanation

What does "estimate" mean, and why round to 1 significant figure?

Estimating means rounding every value in a calculation to make the arithmetic quick and approximate, then calculating with those rounded values — it's not the same as finding the exact answer. Unless told otherwise, round every number in the calculation to 1 significant figure before doing anything else.

02 — Explanation

How do I identify significant figures correctly?

  1. The first significant figure is the first non-zero digit (reading left to right).
  2. Zeros between non-zero digits count as significant: 402402 has 3 s.f.
  3. Leading zeros (before the first non-zero digit) are never significant: 0.0000020.000002 has 1 s.f.
  4. Trailing zeros only count if there's a decimal point: 10001000 has 1 s.f., but 1050.1050. has 4 s.f.

When rounding, use placeholder zeros to keep the number's scale correct: 34,56834{,}568 to 2 s.f. is 35,00035{,}000 (not 3535).

Common Misconception: Rounding 0.0029560.002956 to 2.962.96 — this destroys the place value. It should round to 0.00300.0030 (2 s.f.), keeping the leading zeros that show the number is small.

03 — Explanation

How do I estimate a multi-step calculation?

Round every number to 1 s.f., then apply BIDMAS to the simplified expression — do not round partway through a calculation.

Example: Estimate 9.04+19.85×2.99−5.039.04 + 19.85 \times 2.99 - 5.03.

9+20×3−5=9+60−5=649 + 20 \times 3 - 5 = 9 + 60 - 5 = 64

For division, round the denominator carefully — never let it round to zero. Dividing by 0.50.5 is the same as multiplying by 22, which is a useful shortcut when a rounded value lands on 0.50.5.

Exam Tip: Always show the rounded numbers as part of your working, e.g. "40×400÷8040 \times 400 \div 80" — this secures the method mark even if your final arithmetic slips, and on a calculator paper it's the only proof you actually estimated rather than just computing the exact answer.

04 — Explanation

How do I estimate in a worded, real-life problem?

Round each given value to 1 s.f., calculate, then interpret the result sensibly in context (correct units, whole numbers where the context demands it).

Example: Estimate the cost of 197197 packets of crisps at 4545p each. Round to 200×50p=10,000p=£100200 \times 50\text{p} = 10{,}000\text{p} = £100.

05 — Explanation

How do I estimate a square root that isn't a perfect square?

Find the two perfect squares either side of the number, then judge which one it's closer to.

Example: Estimate 70\sqrt{70}. Since 82=648^2=64 and 92=819^2=81, the answer is between 88 and 99. As 7070 is closer to 6464 (difference 66) than to 8181 (difference 1111), 70\sqrt{70} is a little closer to 88 than 99 — about 8.48.4.

06 — Explanation

How do I tell if an estimate is an overestimate or underestimate, without calculating the exact value?

It depends on which way each number was rounded:

OperationOverestimate when...Underestimate when...
a+ba+b, a×ba \times bboth rounded upboth rounded down
a−ba-b, a÷ba \div baa rounded up and/or bb rounded downaa rounded down and/or bb rounded up

For subtraction and division, rounding both numbers in the same direction makes the effect impossible to determine without checking — the two roundings pull in opposite directions on the result.

07 — Worked example

Worked Example

5252 is rounded to 11 s.f. as 5050, and 7.87.8 is rounded to 11 s.f. as 88. Is the estimate of 52÷7.852 \div 7.8 using these roundings an overestimate or underestimate?

  1. The first number (52→5052 \to 50) was rounded down.
  2. The second number (7.8→87.8 \to 8) was rounded up.
  3. For division, "first down, second up" gives an underestimate — dividing a smaller numerator by a larger denominator makes the result smaller than the true value.